Optimal. Leaf size=85 \[ -\frac{\left (a+\frac{b}{x^2}\right )^{p+1} \left (c+\frac{d}{x^2}\right )^q \left (\frac{b \left (c+\frac{d}{x^2}\right )}{b c-a d}\right )^{-q} \, _2F_1\left (p+1,-q;p+2;-\frac{d \left (a+\frac{b}{x^2}\right )}{b c-a d}\right )}{2 b (p+1)} \]
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Rubi [A] time = 0.0618262, antiderivative size = 85, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {444, 70, 69} \[ -\frac{\left (a+\frac{b}{x^2}\right )^{p+1} \left (c+\frac{d}{x^2}\right )^q \left (\frac{b \left (c+\frac{d}{x^2}\right )}{b c-a d}\right )^{-q} \, _2F_1\left (p+1,-q;p+2;-\frac{d \left (a+\frac{b}{x^2}\right )}{b c-a d}\right )}{2 b (p+1)} \]
Antiderivative was successfully verified.
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Rule 444
Rule 70
Rule 69
Rubi steps
\begin{align*} \int \frac{\left (a+\frac{b}{x^2}\right )^p \left (c+\frac{d}{x^2}\right )^q}{x^3} \, dx &=-\left (\frac{1}{2} \operatorname{Subst}\left (\int (a+b x)^p (c+d x)^q \, dx,x,\frac{1}{x^2}\right )\right )\\ &=-\left (\frac{1}{2} \left (\left (c+\frac{d}{x^2}\right )^q \left (\frac{b \left (c+\frac{d}{x^2}\right )}{b c-a d}\right )^{-q}\right ) \operatorname{Subst}\left (\int (a+b x)^p \left (\frac{b c}{b c-a d}+\frac{b d x}{b c-a d}\right )^q \, dx,x,\frac{1}{x^2}\right )\right )\\ &=-\frac{\left (a+\frac{b}{x^2}\right )^{1+p} \left (c+\frac{d}{x^2}\right )^q \left (\frac{b \left (c+\frac{d}{x^2}\right )}{b c-a d}\right )^{-q} \, _2F_1\left (1+p,-q;2+p;-\frac{d \left (a+\frac{b}{x^2}\right )}{b c-a d}\right )}{2 b (1+p)}\\ \end{align*}
Mathematica [A] time = 0.0433858, size = 110, normalized size = 1.29 \[ -\frac{\left (c x^2+d\right ) \left (a+\frac{b}{x^2}\right )^p \left (\frac{a x^2}{b}+1\right )^{-p} \left (\frac{c x^2}{d}+1\right )^p \left (c+\frac{d}{x^2}\right )^q \, _2F_1\left (-p,-p-q-1;-p-q;\frac{(b c-a d) x^2}{b \left (c x^2+d\right )}\right )}{2 d x^2 (p+q+1)} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.064, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{{x}^{3}} \left ( a+{\frac{b}{{x}^{2}}} \right ) ^{p} \left ( c+{\frac{d}{{x}^{2}}} \right ) ^{q}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a + \frac{b}{x^{2}}\right )}^{p}{\left (c + \frac{d}{x^{2}}\right )}^{q}}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\left (\frac{a x^{2} + b}{x^{2}}\right )^{p} \left (\frac{c x^{2} + d}{x^{2}}\right )^{q}}{x^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (a + \frac{b}{x^{2}}\right )}^{p}{\left (c + \frac{d}{x^{2}}\right )}^{q}}{x^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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